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Lesson 17 · Naming the formula
Four shapes, four machines
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Four shapes, four machines

Every flat shape holds two different questions: how much space is INSIDE (the area, measured in square units like m2\mathrm{m^2} — metres squared), and how far it is AROUND (the perimeter, in plain metres). A rug is area; its fringe is perimeter. Keep those two apart and half this chapter's traps never touch you.

Four area machines to meet, each with a read-aloud form you can own. In every one AA is the area, and every letter beside it is a length in metres. A=l⋅wA = l \cdot w for rectangles (A equals l times w), ll the length, ww the width. A=12bhA = \tfrac{1}{2} b h for triangles (A equals one-half b h), bb the base, hh the height standing straight up from it. A=πr2A = \pi r^2 for circles (A equals pi r squared: rr is the radius, centre to edge, and π\pi is the Greek letter pi, said “pie”, a little more than 3). And A=a+b2⋅hA = \dfrac{a+b}{2} \cdot h for trapezoids (A equals a plus b over two, times h): aa and bb the two parallel sides, hh the distance between them. Today you only match shape to machine — the computing starts next lesson.

Alw

A=l⋅wA = l \cdot w

  • AA= Area (area)
  • ll= Length (length)
  • ww= Width (length)
Rectangle Area solver →
bhA

A=12bhA = \tfrac{1}{2} b h

  • AA= Area (area)
  • bb= Base (length)
  • hh= Height (length)
Area of a Triangle solver →
rA

A=πr2A = \pi r^{2}

  • AA= Area (area)
  • rr= Radius (length)
Area of a Circle solver →
abhA

A=a+b2⋅hA = \frac{a + b}{2} \cdot h

  • AA= Area (area)
  • aa= Parallel side a (length)
  • bb= Parallel side b (length)
  • hh= Height (length)
Trapezoid Area solver →