Grade 11 Math — Functions & Applications · Growing by a ratio
The same percent, again and again
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The same percent, again and again

A=A0(1+r)tA = A_0(1 + r)^t — read aloud, A equals A-nought, times one plus r, to the t. It is one fact wearing three outfits: solve it for the final amount, for the starting amount, or for the rate, and it answers three different exam questions.

The exponent is where compounding lives. Growing 10% a year for 3 years is NOT 30% — it is 1.13=1.3311.1^3 = 1.331, a 33.1% gain, because year two grows on year one's winnings. The gap looks small at three years and enormous at thirty; that gap is the entire business model of a bank.

Two guard rails. The rate must arrive as a DECIMAL before it enters the bracket — a 12 where 0.12 belongs multiplies your answer by an absurd factor, and the size of the answer will tell you so instantly. And when you solve for rr, the escape from the exponent is a ROOT: r=(AA0)1/t1r = \left(\dfrac{A}{A_0}\right)^{1/t} - 1. The total growth divided by t is a tempting shortcut and a wrong one — it always overshoots, because it pretends the early years grew on the same base as the late ones.