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Lesson 27 · The one-third family
Three pours, exactly
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Three pours, exactly

Here's the most satisfying demo in geometry. Take a cone and a cylinder with the SAME circle base and the SAME height. Fill the cone with water and pour it into the cylinder — it takes exactly three pours to fill it. Not roughly three: exactly three, every time. Pointy shapes hold a third of their straight-sided partners, and that third IS the formula: V=13πr2hV = \tfrac{1}{3}\pi r^2 h (read aloud: V equals one-third pi r squared h): rr is the cone's base radius, hh its straight-up height, the same two letters the cylinder used.

Pyramids play the identical game with their prism: V=13BhV = \tfrac{1}{3} B h — one-third base area times height — where BB is the base's area, whatever polygon it happens to be. The family has one house rule: never forget the third. An answer three times too big means your cone quietly became a cylinder while you weren't looking.

hrV

V=13πr2hV = \frac{1}{3} \pi r^{2} h

  • VV= Volume (volume)
  • rr= Base radius (length)
  • hh= Height (length)
Cone Volume solver →
hBV

V=13BhV = \frac{1}{3} B h

  • VV= Volume (volume)
  • BB= Base area (area)
  • hh= Height (length)
Pyramid Volume solver →