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Grade 12 Calculus · Lesson 7 · No lifting the pencil · about 4 minutes
Three conditions
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Three conditions

A function is continuous at aa when you can draw its graph through x=ax = a without lifting the pencil. The precise version is three conditions, checked in order: (1) f(a)f(a) is defined; (2) lim⁡x→af(x)\lim_{x \to a} f(x) exists, meaning both one-sided limits exist and agree; (3) lim⁡x→af(x)=f(a)\lim_{x \to a} f(x) = f(a), read aloud: the limit of f of x as x approaches a equals f of a. All three, or it is not continuous. The trap this lesson names is taking condition (1) for the whole thing: a function can have a perfectly good value at aa and still jump there, or still have its dot floating above a hole. Defined is one condition out of three.

Where continuity is free: polynomials are continuous everywhere; so are sin⁡\sin, cos⁡\cos, exe^x and ∣x∣|x|. A rational function N(x)D(x)\dfrac{N(x)}{D(x)} is continuous wherever D(x)≠0D(x) \ne 0, so its only candidates for trouble are the zeros of the denominator. A piecewise function is continuous inside each piece and needs checking only at the boundaries, where the three conditions earn their keep.