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Lesson 18 · Lapse and pressure
The two profiles the atmosphere hands you
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The two profiles the atmosphere hands you

Before a plume can be modelled, the air it is going into has to be described. Two profiles do almost all of that work: how the temperature falls with height, and how the pressure does.

The environmental lapse rate is Γ=T1−T2Δz\Gamma = \dfrac{T_1 - T_2}{\Delta z} — read aloud gamma equals T-one minus T-two, over delta-z. Say the subscripts out loud once and they will never trouble you again: subscript 1 is the LOWER reading and subscript 2 the upper. T1T_1 and T2T_2 are the two air temperatures, Δz\Delta z is the height between them in metres, and Γ\Gamma is the answer, quoted by long convention in C° per kilometre — so a height in metres owes a ×1000 on the way out. Only the DIFFERENCE of the temperatures enters, which means a Celsius interval and a kelvin interval are the same number and the 273.15 cancels itself.

The sign convention is the standing trap of this lesson, and it is worth stating as a rule: lower minus upper, so an atmosphere that cools with height comes out POSITIVE. The dry adiabatic rate is 9.8 C°/km and it is the yardstick — above it the air is superadiabatic and unstable, plumes loop and briefly touch down; below it, stable; below zero it is an inversion, and a plume caught under one goes nowhere at all.

The barometric equation for an isothermal layer is P=P0 e−Mgz/RTP = P_0\,e^{-Mgz/RT} — P equals P-nought e to the minus M g z over R T. P0P_0 is the pressure at the reference level, PP the pressure a height zz above it, MM the molar mass of dry air (0.0290 kg/mol), gg gravity, RR the gas constant (8.314 J/mol·K) and TT the layer's absolute temperature in kelvin. That last word is not a formality: this is a gas law with a hill in it, and Celsius breaks it outright.

Read the shape of it. RT/MgRT/Mg is the scale height, about 8.4 km, the height over which pressure falls by a factor of e. And know the assumption you just made: the real atmosphere is not isothermal, so at 1000 m this form gives 90.0 kPa where the true standard atmosphere gives 89.9. That 0.1 kPa is the assumption, not an arithmetic slip — and saying which is which out loud is most of what separates an engineer from a calculator.

zTT1T2ΓΔz

Γ=T1−T2z2−z1\Gamma = \frac{T_1 - T_2}{z_2 - z_1}

  • Γ\Gamma= Lapse rate (°C/km)
  • T1T_1= Temperature below (temperature)
  • T2T_2= Temperature above (temperature)
  • Δz\Delta z= Height difference (length)
Environmental Lapse Rate solver →
zPP0PzT

P=P0 e−Mgz/RTP = P_0 \, e^{-Mgz/RT}

  • PP= Pressure at height (pressure)
  • P0P_0= Reference pressure (pressure)
  • zz= Height above reference (length)
  • TT= Layer temperature (temperature)
Barometric Pressure with Altitude solver →