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Lesson 21 · Plume rise
Why rise is worth more than steel
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Why rise is worth more than steel

A plume leaves a stack hot and moving, and it keeps climbing. The metres it gains are added to the stack's own height and dispersion starts from the sum — and because ground-level concentration falls with the SQUARE of that sum, plume rise is the cheapest height in the industry.

The modern route is Briggs, in two steps. First the buoyancy flux F=g vs d2(Ts−Ta)4 TsF = \dfrac{g\,v_s\,d^{2}(T_s - T_a)}{4\,T_s} — F equals g v-s d squared, T-s minus T-a, over four T-s. Subscript s is the stack gas and subscript a the ambient air, both temperatures absolute, in kelvin; vsv_s is the exit velocity in m/s and dd the inside diameter in metres. FF comes out in m⁴/s³ and is not a length, a speed, or anything you can picture — it is the plume's lifting power in one number. Note that the difference on top would survive a Celsius slip and the TsT_s underneath would not, which is exactly why that slip is so quiet.

Then the two-thirds law, Δh=1.6 F1/3x2/3u\Delta h = \dfrac{1.6\,F^{1/3} x^{2/3}}{u} — delta-h equals one point six, F to the one-third, x to the two-thirds, over u. xx is the downwind distance in metres, uu the wind at stack top in m/s, and Δh\Delta h the rise in metres. Read the exponents: buoyancy enters WEAKLY at one-third, distance strongly at two-thirds, and the wind divides — which is why the calm hours give the worst ground-level numbers, not the windy ones.

Be honest about what that equation is: transitional rise, valid until the plume levels off. Briggs puts final rise near 3.5x∗3.5x^*, with x∗x^* about 14F5/814F^{5/8} below F = 55 m⁴/s³ and 34F2/534F^{2/5} above it — past that distance the plume has stopped climbing and this form over-predicts. A paper that asks for the value at 1 km wants the value at 1 km; a real assessment caps it.

Holland's 1953 equation is the screening alternative, doing momentum and buoyancy in one pass: Δh=vsdu(1.5+2.68×10−3Pd Ts−TaTs)\Delta h = \dfrac{v_s d}{u}\left(1.5 + 2.68\times10^{-3} P d\,\dfrac{T_s - T_a}{T_s}\right). The 1.5 is the momentum term, which a cold plume still gets; the second term is buoyancy. PP is atmospheric pressure and Holland's constant was written for millibars — feed it pascals and the plume goes to the stratosphere. Holland is generally conservative, which is its whole value: if the screening number already clears the limit, the fuller treatment will only be kinder.

Either way it ends the same: H=hs+ΔhH = h_s + \Delta h, the effective stack height, where hsh_s is the steel and HH is what every dispersion equation actually uses.

vsdTsFTa

F=g vs d2(Ts−Ta)4 TsF = \frac{g \, v_s \, d^2 (T_s - T_a)}{4 \, T_s}

  • FF= Buoyancy flux (m⁴/s³)
  • vsv_s= Stack exit velocity (speed)
  • dd= Stack inside diameter (length)
  • TsT_s= Stack gas temperature (temperature)
  • TaT_a= Ambient temperature (temperature)
Briggs Buoyancy Flux solver →
ΔhxuF

Δh=1.6 F1/3x2/3u\Delta h = \frac{1.6 \, F^{1/3} x^{2/3}}{u}

  • Δh\Delta h= Plume rise (length)
  • FF= Buoyancy flux (m⁴/s³)
  • xx= Downwind distance (length)
  • uu= Wind speed at stack height (speed)
Briggs Plume Rise (Neutral and Unstable) solver →
vsdΔhuTsTaP

Δh=vsdu(1.5+2.68×10−3Pd Ts−TaTs)\Delta h = \frac{v_s d}{u}\left(1.5 + 2.68\times10^{-3} P d \, \frac{T_s - T_a}{T_s}\right)

  • Δh\Delta h= Plume rise (length)
  • vsv_s= Stack exit velocity (speed)
  • dd= Stack inside diameter (length)
  • uu= Wind speed at stack height (speed)
  • PP= Atmospheric pressure (pressure)
  • TsT_s= Stack gas temperature (temperature)
  • TaT_a= Ambient temperature (temperature)
Holland Plume Rise solver →
hsΔhH

H=hs+ΔhH = h_s + \Delta h

  • HH= Effective stack height
  • hsh_s= Physical stack height
  • Δh\Delta h= Plume rise

each variable a length

Effective Stack Height solver →