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Lesson 24 · Whole-wall heat loss
Watts on the design day
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Watts on the design day

Now we cash the R-value in. Q˙=A ΔTRtot\dot{Q} = \dfrac{A \, \Delta T}{R_{tot}} — read aloud Q-dot equals A delta-T over R-total. Q˙\dot{Q} is the heat loss rate in watts (the dot means “per second” — it is a rate, not a quantity of energy), AA is the assembly's area in square metres, ΔT\Delta T is the inside-to-outside temperature difference in kelvin, and RtotR_{tot} is the total R-value in m²·K/W.

Drop the area and you get the same idea per square metre: q′′=ΔTRq'' = \dfrac{\Delta T}{R} — q double-prime equals delta-T over R, the heat flux, in W/m². The two primes are the trade's way of writing “per unit area”. Flux is what a thermographer measures and what a designer compares between assemblies, because it does not care how big the wall is.

The design day is where the numbers come from: an indoor set point, usually 20 to 22 °C, against the outdoor temperature the local code says to size for. Watch the sign — 21 °C indoors against −14 °C outdoors is a 35 K difference, not 7. The minus sign in front of the outdoor figure is the single most expensive character in a heat-loss spreadsheet.

Estimate before you compute, every time. A code wall runs somewhere near ten watts a square metre on a cold day, so 40 m² of it is a few hundred watts — about a hair dryer's worth, running all winter. Hold that scale in your head and a slipped decimal announces itself before the calculator does.

ΔTAQRtot

Q˙=A ΔTRtot\dot{Q} = \frac{A \, \Delta T}{R_{tot}}

  • Q˙\dot{Q}= Heat loss rate (power)
  • AA= Assembly area (area)
  • ΔT\Delta T= Inside-to-outside ΔT (temperature difference)
  • RtotR_{tot}= Total assembly R-value (areal thermal resistance)
Heat Loss Through an Assembly (Q = A·ΔT/R) solver →
ΔTq″R

q′′=ΔTRq'' = \frac{\Delta T}{R}

  • q′′q''= Heat flux (intensity)
  • ΔT\Delta T= Temperature difference (temperature difference)
  • RR= R-value of the assembly (areal thermal resistance)
Heat Flux Through Insulation (q = ΔT/R) solver →