Rhombus Area (from Diagonals)

Also known as area of a rhombus · diamond area · half product of diagonals

A=d1d22A = \frac{d_1 d_2}{2}

Worked example: diagonals 6 m and 8 m → 24 m^2 — press Try an example to run it live, then adjust anything.

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Rhombus Area (from Diagonals) explained

d1d2A

A rhombus is a quadrilateral with four equal sides — a square that has been leaned over. Its two diagonals cross at right angles and each cuts the other exactly in half, and those two facts hand you the area at once. The crossing splits the shape into four right triangles, each with legs d1/2d_1/2 and d2/2d_2/2, so the total is 4×12(d12)(d22)=12d1d24 \times \tfrac{1}{2}\left(\tfrac{d_1}{2}\right)\left(\tfrac{d_2}{2}\right) = \tfrac{1}{2}d_1 d_2. The tidier picture: draw the smallest rectangle that boxes the rhombus in, with sides d1d_1 and d2d_2. The rhombus fills exactly half of it, because each of the four corner triangles left over is congruent to one inside.

The reason this form beats base × height is purely practical: on a real diamond-shaped object the diagonals are the measurements you can take. A leaded window pane 340 mm corner to corner the long way and 190 mm the short way is 12(0.34)(0.19)=0.0323\tfrac{1}{2}(0.34)(0.19) = 0.0323 m² of glass. Measuring the perpendicular height of a leaning shape, by contrast, means holding a square against nothing in particular.

Set d1=d2d_1 = d_2 and you have a square standing on its corner, of area d2/2d^2/2 — which says a square rotated 45° inside a box fills half of it, a fact worth recognising on sight. The formula also generalises further than its name suggests: half the product of the diagonals is the area of any quadrilateral whose diagonals meet at right angles, the rhombus and the kite both being special cases.

Three ways this goes wrong. The commonest is entering half-diagonals — the distance from the centre out to a tip rather than tip to tip — which quarters the answer. The second is reaching for the side length instead: a rhombus is not determined by its sides, and that is the point. Fix the four sides and hinge the corners, and the shape sweeps continuously from a square with area s2s^2 down to a collapsed line with no area at all, all the way keeping the same perimeter. There is no area formula from ss alone; you need the lean, either as a pair of diagonals or as A=s2sin⁡θA = s^2 \sin\theta. The third is verifying you have a rhombus at all — if the diagonals do not bisect each other, it is a kite or a general quadrilateral, and only the perpendicularity is doing the work here.

Rhombus Area (from Diagonals) formula

A=d1d22A = \frac{d_1 d_2}{2}
Where
  • AA= Area (m²)
  • d1d_1= Diagonal 1 (m)
  • d2d_2= Diagonal 2 (m)

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