Grade 11 Chemistry · Counting particles
How big is 10²³, really
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How big is 10²³, really

N=nNAN = n\,N_Acapital-N equals n times N-A — turns a headcount in moles into actual things: multiply by 6.02×10236.02 \times 10^{23}. Read the subscript aloud as “N sub A”; the A is for Avogadro, who never measured it and has it named after him anyway, which is science being generous.

Try to feel the size, because the exponent is the entire lesson. A mole of grains of sand would bury Canada kilometres deep. A mole of seconds is about ten thousand times the age of the universe. If you counted molecules at one per second you would need 2×10162 \times 10^{16} years to finish a teaspoon of water. So when a magnitude stage asks for the power of ten, answer it before you touch a key: a couple of moles is always somewhere around 102410^{24}, and any answer that comes back as a normal-looking number has been divided when it should have been multiplied.