Potential Temperature (Poisson's Equation)

Also known as potential temperature · theta · Poisson equation potential temperature · dry adiabatic temperature at 1000 hPa · temperature brought to 1000 hPa · θ = T (P0/P)^(R/cp) · air parcel temperature at reference pressure · meteorology theta from temperature and pressure · isentropic temperature

θ=T(p0p)Rd/cp\theta = T\left(\frac{p_0}{p}\right)^{R_d/c_p}
sig figs

Worked example: −32.716 °C at 500 hPa → 20 °C at 1000 hPa (exponent 0.286). Press Try an example to run it live, then adjust anything.

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Potential Temperature (Poisson's Equation) explained

more pressurepp0Tθdry, no heat

Temperature alone cannot say whether two parcels of air really differ. Air that rises expands and cools, and air that sinks is compressed and warms, with no heat added or taken away. Potential temperature takes that pressure effect out. It is the temperature a parcel of dry air would have if it were brought, without gaining or losing heat, to the reference pressure p0p_0, usually 1000 hPa. A parcel that rises or sinks dry keeps the same θ\theta while its TT changes, so θ\theta is the label that tells two air masses apart at different heights.

In θ=T(p0/p)Rd/cp\theta=T(p_0/p)^{R_d/c_p}, TT is the air temperature at the pressure pp of the level you are looking at, and the calculation is done on the absolute scale (20 °C is 293.15 K). Where pp is below p0p_0, the ratio p0/pp_0/p is above one, so θ\theta comes out warmer than TT; where pp equals p0p_0 the two agree. The exponent is the gas constant of dry air over its specific heat, about 0.2856. It comes from the first law of thermodynamics combined with the ideal gas law for a parcel that exchanges no heat, which is how Holton and Hakim derive it in chapter 2 of An Introduction to Dynamic Meteorology.

The page's example is air at -32.716 °C and 500 hPa, with the reference at 1000 hPa; the result is 20 °C. Read the other way, a 20 °C parcel at 1000 hPa lifted dry to 500 hPa has T=293.15×0.50.286=240.434T=293.15\times0.5^{0.286}=240.434 K, which is -32.716 °C, so the thermometer reading falls with height while θ\theta stays at 20 °C. The same relation can be rearranged for pp or p0p_0; fed the 20 °C and -32.716 °C pair, it returns the 500 hPa or the 1000 hPa you started with.

Read the answer by comparing it between heights. If θ\theta rises with height, the air is stable; if it falls, the air overturns. Since a dry parcel carries its own θ\theta with it, a layer whose θ\theta rises with height resists vertical movement and a layer whose θ\theta falls does not. The formula is for dry air and for a parcel that neither gains nor loses heat. Wikipedia gives the exponent as 0.286, while this page uses 287.0528 / 1005 = 0.28562. The two agree to 0.13 % in the exponent, which is 0.1 K on the potential temperature, so a hand calculation with 0.286 can differ by about that.

Potential Temperature (Poisson's Equation)

θ=T(p0p)Rd/cp\theta = T\left(\frac{p_0}{p}\right)^{R_d/c_p}
Where
  • θ\theta= Potential temperature (°C)
  • TT= Air temperature (°C)
  • pp= Air pressure (hPa)
  • p0p_0= Reference pressure (hPa)
Where this comes from
  • Holton, J. R., & Hakim, G. J. (2013). An Introduction to Dynamic Meteorology (5th ed.). Academic Press, chapter 2 (potential temperature from the first law and the ideal gas law).
Revised 30 October 2026
Cite this page

formula.expert. (2026, October 30). Potential Temperature (Poisson's Equation) Calculator. https://formula.expert/solvers/potential-temperature