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ft⋅lbf/(lb⋅∘R)\text{ft}{\cdot}\text{lbf/(lb}{\cdot}^{\circ}\text{R)}

foot pound-force per pound-Rankine

Specific heat capacity

The foot pound-force per pound-Rankine is 5.380320456 J/(kg·K). It is not really a specific heat unit; it is the unit US thermodynamics texts quote the specific gas constant in, and the gas constant shares its dimensions. Air is 53.35 ft·lbf/(lb·°R), which is the same statement as 287.1 J/(kg·K).

1 ft⋅lbf/(lb⋅∘R)\text{ft}{\cdot}\text{lbf/(lb}{\cdot}^{\circ}\text{R)} 5.3803205 J/(kg⋅K)\text{J/(kg}{\cdot}\text{K)}
Where the unit came from

The unit exists because early US engineering thermodynamics kept mechanical work in foot-pounds and heat in BTU, refusing to admit they were the same quantity. The mechanical equivalent of heat, 778.17 ft·lbf per BTU, is the bridge between this unit and BTU/(lb·°R).

One foot pound-force per pound-rankine in every specific heat capacity unit

5.38032joule per kilogram-kelvin (J/(kg·K))
5.38032joule per kilogram-Celsius (J/(kg·°C))
1foot pound-force per pound-Rankine (ft·lbf/(lb·°R))this unit
0.00538032kilojoule per kilogram-kelvin (kJ/(kg·K))
0.00538032kilojoule per kilogram-Celsius (kJ/(kg·°C))
0.00538032joule per gram-kelvin (J/(g·K))
0.00128593calorie per gram-Celsius (cal/(g·°C))
0.00128593kilocalorie per kilogram-Celsius (kcal/(kg·°C))
0.00128507BTU per pound-Fahrenheit (BTU/(lb·°F))
0.00128507BTU per pound-Rankine (BTU/(lb·°R))
Solvers that use specific heat capacity

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formula.expert. (n.d.). Foot pound-force per pound-Rankine (ft·lbf/(lb·°R)): definition & conversion. https://formula.expert/units/foot-pound-force-per-pound-rankine