Radar and Radio Horizon with Standard Refraction

Also known as radio horizon · radar horizon · line of sight distance with refraction · 4/3 earth radius · effective Earth radius factor · k factor horizon · how far can a radar see · ADS-B receiver range · VHF line of sight · 4.12 square root of height · effective earth radius k = 4/3 · microwave link horizon

d=h (2kR+h)≈2kRh,k=43 ⇒ d≈4.12h (d in km, h in m)d = \sqrt{h\,(2kR + h)} \approx \sqrt{2kRh},\qquad k = \tfrac{4}{3}\ \Rightarrow\ d \approx 4.12\sqrt{h}\ (d\text{ in km},\ h\text{ in m})
sig figs

Worked example: Wikipedia: eye at 1.70 m, no bending → 4.7 km. Press Try an example to run it live, then adjust anything.

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Radar and Radio Horizon with Standard Refraction explained

hdkRhorizon

This gives the distance to the horizon for radio or radar from the height hh of an antenna, or of an aircraft, above the surface. The air is thinner higher up, so a beam that starts out level curves gently down toward the ground and reaches farther than a straight line would. Recommendation ITU-R P.834 handles that by keeping the beam straight and enlarging the Earth to an effective radius kRkR, kk times the real one. The horizon is then the tangent from the antenna to that bigger sphere, d=h (2kR+h)d = \sqrt{h\,(2kR + h)}, which is about 2kRh\sqrt{2kRh} when hh is small beside the radius.

For the standard atmosphere k=4/3k = 4/3, and the result is about 4.12h4.12\sqrt{h} kilometres with hh in metres. The bare geometry of the library's horizon-distance-from-height page has 3.57 in place of 4.12, so the radio horizon is about 15 percent farther than the geometric one. Because the distance grows only as the square root of the height, a taller mast brings diminishing returns. Two antennas that can just see each other are separated by the sum of their two horizon distances, one for each height. Entering k=1k = 1 gives the geometric horizon with no bending.

Two cases printed on Wikipedia, rounded as printed there, show the scale. An eye 1.70 m above the sea, with no bending (k=1k = 1), sees 4.7 km; the page gives 4.654 km, and that is the example it offers. A 1 500 m mast or aircraft altitude with k=4/3k = 4/3 sees to about 160 km, from 4.121 5004.12\sqrt{1\,500}. The page uses the exact tangent, 159.64 km, which is 0.2 percent less. Run backwards, a horizon of 159.64424575 km at k=4/3k = 4/3 returns the height of 1 500 m, and by hand a 25 m mast at k=4/3k = 4/3 sees 20 609.09 m.

The factor kk is an average, and it is the weak point of the method. In strong temperature inversions it can be much larger, with ducting, and in very dry, cold or unstable air it is smaller. Recommendation ITU-R P.834-9 (12/2017), section 2, gives k=4/3k = 4/3 for heights below 1 000 m, so the 1 500 m case above is a step beyond it.

Radar and Radio Horizon with Standard Refraction formula

d=h (2kR+h)≈2kRh,k=43 ⇒ d≈4.12h (d in km, h in m)d = \sqrt{h\,(2kR + h)} \approx \sqrt{2kRh},\qquad k = \tfrac{4}{3}\ \Rightarrow\ d \approx 4.12\sqrt{h}\ (d\text{ in km},\ h\text{ in m})
Where
  • dd= Distance to the radio horizon (km)
  • hh= Antenna height above the surface (m)
  • kk= Effective Earth radius factor
Where this comes from
  • International Telecommunication Union, Recommendation ITU-R P.834-9 (12/2017), Effects of tropospheric refraction on radiowave propagation, section 2, 'Effective Earth radius', read 23 Oct 2026 from the pdf at itu.int (and the 2003 edition, P.834-4, which the wanted list cites, with the same text): a constant refractivity gradient is handled by 'a hypothetical Earth of effective radius R_e = k a', with a the actual Earth radius and k the effective earth radius factor, and 'for heights below 1 000 m ... the corresponding k-factor is k = 4/3'. Read it
Revised 30 October 2026
Cite this page

formula.expert. (2026, October 30). Radar and Radio Horizon with Standard Refraction Calculator. https://formula.expert/solvers/radio-horizon-effective-earth-radius