Shallow Concentrated Flow Velocity

Also known as V = Ku k Sp^0.5 · shallow concentrated flow · overland flow velocity from slope · intercept coefficient velocity slope relationship · HDS-2 velocity versus slope · TR-55 shallow concentrated flow · velocity in rills and gullies · velocity of runoff before the channel · time of concentration velocity method segment · paved unpaved grassed waterway velocity · HEC-22 equation 4.4

V=Ku k SpV = K_u\,k\,\sqrt{S_p}
m/s at a 1 % slope
sig figs

Worked example: SI, Ku = 1: k 0.305, slope 4 % → 0.61 m/s. Press Try an example to run it live, then adjust anything.

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Shallow Concentrated Flow Velocity explained

SpVk

Between sheet flow and a defined channel, runoff gathers into rills and small gullies. The Federal Highway Administration's urban drainage manual (HEC-22, fourth edition, equation 4.4, from HDS 2) gives the average velocity of that stage from the slope alone: V=KukSpV = K_u k \sqrt{S_p}, where kk is an intercept coefficient picked from a table by land cover, SpS_p is the slope in percent and KuK_u is a unit constant, 3.28 for feet per second and 1.0 for metres per second. The page works in metres per second, so KuK_u is 1 and the velocity is kk times the square root of the slope in percent.

The coefficient kk is the velocity at a slope of 1 percent. Table 4.3 runs from 0.076 for forest with heavy ground litter or hay meadow, through 0.213 for short grass pasture, 0.305 for nearly bare and untilled ground, 0.457 for a grassed waterway and 0.491 for unpaved shallow concentrated flow, up to 0.619 for paved areas or small upland gullies. The slope enters as a square root, so the velocity rises with slope but more slowly than the slope does. Watch the units: SpS_p is in percent, so 0.6 percent is 0.006 ft/ft.

The manual's Example 4.2, step 1b, is the page's check. A grassed waterway at a slope of 0.006 ft/ft (0.6 percent) with k=0.457k = 0.457 gives 1.16 ft/s; the page gives 0.35398 m/s, which is 1.1614 ft/s. In metric units, nearly bare ground with k=0.305k = 0.305 at a slope of 4 percent gives 0.305×4=0.610.305 \times \sqrt{4} = 0.61 m/s, and read backwards that velocity returns k=0.305k = 0.305. This is the middle leg of a time of concentration, between sheet flow and open channel or pipe flow: divide its length by the velocity to get its travel time.

Say which table you used. The Natural Resources Conservation Service's National Engineering Handbook, Part 630, chapter 15 (Table 15-3), has the same relation with its own coefficient table, and its values differ from HEC-22's on the grassed waterway row. For paved ground its form V=20.328 s0.5V = 20.328\, s^{0.5}, in feet per second with ss in ft/ft, gives 1.2857 ft/s at s=0.004s = 0.004, where HEC-22's k=0.619k = 0.619 gives 1.2844 ft/s; the handbooks round their coefficients to different places. The NRCS form applies to slopes less than 0.005 ft/ft, while HEC-22 sets no limit on slope for its equation.

Shallow Concentrated Flow Velocity formula

V=Ku k SpV = K_u\,k\,\sqrt{S_p}
Where
  • VV= Average velocity (m/s)
  • kk= Intercept coefficient (m/s at a 1 % slope)
  • SpS_p= Slope (%)
Where this comes from
  • US Department of Transportation, Federal Highway Administration, Urban Drainage Design, Hydraulic Engineering Circular No. 22 (HEC-22), Fourth Edition, publication FHWA-HIF-24-006, February 2024, section 4.2.2.3 Time of Concentration, equation 4.4 (V = Ku k Sp^0.5, Ku = 3.28 in customary units and 1.0 in SI, Sp in percent) and Table 4.3 (intercept coefficients, printed pages 27 and 28); worked in Example 4.2 step 1b (printed page 30). The same relation with a different coefficient table: NRCS National Engineering Handbook Part 630 chapter 15 Time of Concentration (210-VI-NEH, May 2010), Table 15-3. Read it
Revised 30 October 2026
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formula.expert. (2026, October 30). Shallow Concentrated Flow Velocity Formula & Calculator. https://formula.expert/solvers/shallow-concentrated-flow-velocity