Ionic Product of Water (Kw at 25 °C)

Kw=1×10−14K_{\mathrm{w}} = 1 \times 10^{-14}
Value1 × 10⁻¹⁴
StatusMeasured: ± 1 × 10⁻¹⁶ (1 % relative)
SourceIAPWS R11-07(2019), Revised Release on the Ionization Constant of H2O (Bandura and Lvov 2006): pKw 13.995 at 25 °C and 0.1 MPa, so Kw = 1.01 × 10⁻¹⁴, conventionally rounded to 1.0 × 10⁻¹⁴
CategoriesChemistryWater Treatment

Learning zone

Water is faintly self-ionising: about one molecule in 5.5 × 10⁸ has handed a proton to a neighbour at any instant, giving H₃O⁺ and OH⁻ at 1.0 × 10⁻⁷ mol/L each. The product of those two concentrations is fixed at any given temperature, and at 25 °C it is 1.0 × 10⁻¹⁴, which is the only reason pH + pOH = 14 and the only reason pH 7 means neutral. Careful conductance work puts the measured value slightly higher, pKw = 13.995 or Kw = 1.01 × 10⁻¹⁴; the round 1.0 × 10⁻¹⁴ is a convention that survives because it is within a rounding error of the truth and makes the arithmetic clean.

The temperature caveat is not academic. Autoionisation is endothermic, so heating drives it forward: at 0 °C, Kw = 1.14 × 10⁻¹⁵ and neutral water sits at pH 7.47; at 100 °C, Kw = 5.1 × 10⁻¹³ and neutral is pH 6.14. Inside a boiler drum at 300 °C, pKw has fallen to roughly 11.3, so neutral is near pH 5.7: a hot condensate line reading pH 6 is not acidic, it is neutral, and a plant chemist who forgets that will dose caustic into water that never needed it. Note also that the water has not become acidic in any of these cases: [H⁺] and [OH⁻] rise together and stay equal.

Revised 8 November 2026
Cite this page

formula.expert. (2026, November 8). Ionic Product of Water (Kw at 25 °C). https://formula.expert/constants/ionic-product-of-water