pH and pOH Relation

Also known as pH plus pOH equals 14

pH+pOH=14\mathrm{pH} + \mathrm{pOH} = 14

Units aren’t used in this calculation: every value is a plain number.

sig figs

Worked example: pH 4.75 → pOH = 9.25. Press Try an example to run it live, then adjust anything.

Enter your known values, leave one input blank, and solves for the missing one. Tap a variable’s symbol to see what it means, with a typical value.

Where pH and pOH Relation fits

Missing an input?
Your answer feeds
In this toolkit

See also

pOH from Hydroxide Ion Concentration: Where a pOH comes from when you have a hydroxide concentration rather than a pH.Henderson–Hasselbalch Equation (Weak Base Buffer): Both use poh.Henderson–Hasselbalch Equation (Weak Acid Buffer): Both use ph.pH from Hydrogen Ion Concentration: Both use ph.pH of a Weak Acid from Ka: Both use ph.pH of a Weak Base from Kb: Both use ph.
4 more relatedCooling Tower LSI at Cycles of Concentration: Both use ph.Langelier Saturation Index (LSI): Both use ph.Langelier Saturation Index from a Full Water Analysis: Both use ph.Ryznar Stability Index (RSI): Both use ph.
Here the solver did the work. Could you?

pH plus pOH →

Grade 11Grade 11 Chemistry

The pH scale →

Grade 12Grade 12 Chemistry

Test your skills in the Exam Room: new numbers every attempt. Free lessons for students, no sign-up, just pure learning. Find 3 more lessons on this formula.

See your Report Card
Learning zone

pH and pOH Relation explained

pHpOH

Water is never merely water. A small fraction of it is always pulled apart into H⁺ and OH⁻, and the equilibrium between them fixes the product of their concentrations at a constant: Kw=[H+][OH−]=1.0×10−14K_w = [\text{H}^+][\text{OH}^-] = 1.0\times10^{-14} at 25 °C. Because it is a product that is constant, the two concentrations are locked in a see-saw: push one up and the other must come down by the same factor. Take negative logarithms of both sides and the product becomes a sum: pH+pOH=14\mathrm{pH} + \mathrm{pOH} = 14. So pH and pOH are not two independent measurements. They are one number written two ways, and knowing either gives the other for free.

A worked case. Dissolve enough sodium hydroxide to make a 0.010 M solution: it dissociates completely, so [OH−]=1.0×10−2[\text{OH}^-] = 1.0\times10^{-2} and pOH = 2.00. Then pH = 14 − 2.00 = 12.00. Check it the long way, [H+]=Kw/[OH−]=10−14/10−2=10−12[\text{H}^+] = K_w/[\text{OH}^-] = 10^{-14}/10^{-2} = 10^{-12}, giving pH 12.00, and the two routes agree, as they must.

The "14" is not a magic number, it is pKw\mathrm{p}K_w, and the exact value at 25 °C is 13.995. The whole logarithmic apparatus came from Søren Sørensen at the Carlsberg laboratory in 1909, who needed a compact way to talk about hydrogen ion concentrations spanning more than ten orders of magnitude in brewing. The p-prefix now attaches to anything worth compressing that way: pOH, pKa, pKw, pCa.

The trap is that 14 belongs to 25 °C and nothing else. Self-ionisation is endothermic, so heating water drives it forward and KwK_w rises: pKw is about 14.9 at 0 °C, 13.0 at 60 °C, and 12.0 at 100 °C. Which means neutral water at 100 °C has a pH of 6.0, and it is still perfectly neutral, not acidic, because pH still equals pOH. This matters wherever hot water is measured: boiler water sampled at temperature and boiler water sampled after cooling do not read the same, and the difference is the equation moving, not the chemistry changing. Anyone reading pH on a hot sample needs to know whether the meter is compensating and what reference temperature it is compensating to.

Which leads to the deeper misconception. Neutral does not mean pH 7; neutral means pH equals pOH. The two coincide at 25 °C by arithmetic accident, and part company at every other temperature. Two smaller notes: the relation is aqueous only (it says nothing about a non-aqueous solvent, which has its own autoionisation constant if it has one at all) and the pH scale is not fenced between 0 and 14. Those bounds are just where 1 M solutions land. Concentrated hydrochloric acid at 12 M has a negative pH, and concentrated sodium hydroxide runs above 14, with the sum still holding.

pH and pOH Relation formula

pH+pOH=14\mathrm{pH} + \mathrm{pOH} = 14
Where
  • pH\mathrm{pH}= pH
  • pOH\mathrm{pOH}= pOH
Revised 31 October 2026
Cite this page

formula.expert. (2026, October 31). pH and pOH Relation Formula & Calculator. https://formula.expert/solvers/ph-poh-relation