Area Moment of Inertia — Rectangle

I=bh312I = \frac{b h^{3}}{12}

Enter your known values, leave one input blank, and solves for the missing one. Try different units for next level excitement!

Learning zone

The second moment of area measures how far a section's material sits from the axis it bends about — and because the contribution goes as distance squared, it rewards depth enormously. For a rectangle, I = bh³/12 about the axis through the centroid perpendicular to h. A 50 mm × 100 mm bar bending about its strong axis has I = 0.05 × 0.1³ ÷ 12 = 4.167 × 10⁻⁶ m⁴; turn it flat and h and b swap, giving 1.042 × 10⁻⁶ m⁴, a quarter as stiff. Double the depth alone and stiffness goes up eightfold — the whole reason joists stand on edge and I-beams put their steel in the flanges.

This engine has no m⁴ unit type, so I is entered and returned as a plain number in m⁴: 1 in⁴ = 4.162314 × 10⁻⁷ m⁴ and 1 mm⁴ = 10⁻¹² m⁴. The trap is the cube: get b and h the wrong way round and you are not off by a little, you are off by (h/b)⁴ — for a 2 × 8 that is a factor of 16. And this formula is only valid about the centroidal axis; if the rectangle is a flange offset from the neutral axis of a built-up section, you must add the parallel-axis term Ad².

Area Moment of Inertia — Rectangle
I=bh312I = \frac{b h^{3}}{12}
Where
  • II= Area moment of inertia
  • bb= Width (parallel to the axis)
  • hh= Depth (perpendicular to the axis)
Missing one of these? Work it out first, then come back