Arrhenius Two-Temperature Form
Worked example: Rate doubles 300 K → 310 K: Ea = 53.597 kJ/mol — press Try an example to run it live, then adjust anything.
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Grade 12Grade 12 Chemistry
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Arrhenius Two-Temperature Form explained
Write the Arrhenius equation twice, once at each temperature, and divide: the pre-exponential factor A cancels and only the ratio of rate constants survives. That is a gift to the experimentalist, because A is hard to measure but a rate ratio needs only two runs on the same apparatus. Since only k₂/k₁ appears, the units of the rate constants are irrelevant as long as both are the same — half-lives work just as well, inverted.
The classic result: a reaction whose rate exactly doubles between 300 K and 310 K has = R ln 2 / (1/300 − 1/310) = 8.314 × 0.693 × 9300 = 53.6 kJ/mol. That is where the "rates double every 10 degrees" rule of thumb comes from — it is only true for activation energies near 50 kJ/mol, and it fails badly for very fast or very slow reactions. The two traps are using Celsius instead of kelvin (this calculator converts for you, but a hand calculation will be wildly wrong) and reversing the reciprocal difference, which flips the sign and hands you a negative activation energy.
Arrhenius Two-Temperature Form formula
- = Rate constant at T1 (Hz)
- = Rate constant at T2 (Hz)
- = Activation energy (kJ/mol)
- = First absolute temperature (°C)
- = Second absolute temperature (°C)
Missing one of these? Work it out first, then come back
- Rate constant at T1 — Arrhenius Equation, Radioactive Activity (A = λN)
- Rate constant at T2 — Arrhenius Equation, Radioactive Activity (A = λN)
- Activation energy — Arrhenius Equation, Activation Energy from an Arrhenius Plot
- First absolute temperature — van 't Hoff Equation (K at Two Temperatures), Gas Density from Molar Mass
- Second absolute temperature — van 't Hoff Equation (K at Two Temperatures), Gas Density from Molar Mass