Brewster's Angle

tanθB=n2n1\tan\theta_B = \frac{n_2}{n_1}

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At one special angle the reflected and refracted rays are exactly perpendicular, and light polarized in the plane of incidence cannot reflect at all — everything that bounces off is polarized parallel to the surface. For water (n = 1.333) from air that angle is arctan(1.333) ≈ 53.1°. Polarized sunglasses are oriented to block exactly that component, which is why they kill the glare off a lake at low sun but do little at noon.

Brewster's Angle
tanθB=n2n1\tan\theta_B = \frac{n_2}{n_1}
Where
  • θB\theta_B= Brewster's angle
  • n1n_1= Index of the incident medium
  • n2n_2= Index of the reflecting medium
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