Two Capacitors in Parallel

Ct=C1+C2C_{t} = C_{1} + C_{2}

Enter your known values, leave one input blank, and solves for the missing one. Try different units for next level excitement!

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Wired in parallel, both capacitors see the same voltage, and their plate areas effectively pool into one bigger capacitor — so capacitances simply add. A 4.7 µF and a 2.2 µF part side by side behave as 6.9 µF. Designers exploit this to hit odd values, or to pair a big bulk capacitor with a small fast one.

Two Capacitors in Parallel
Ct=C1+C2C_{t} = C_{1} + C_{2}
Where
  • CtC_{t}= Total capacitance
  • C1C_{1}= Capacitance 1
  • C2C_{2}= Capacitance 2
Missing one of these? Work it out first, then come back