Two Capacitors in Series

Ct=C1C2C1+C2C_{t} = \frac{C_{1} C_{2}}{C_{1} + C_{2}}

Enter your known values, leave one input blank, and solves for the missing one. Try different units for next level excitement!

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Capacitors combine opposite to resistors. In series the same charge sits on every capacitor while the voltages stack, so the reciprocals add — 1/Cₜ = 1/C₁ + 1/C₂, the product-over-sum shortcut for two — and the total is always smaller than either capacitor alone. Two equal 10 µF parts in series make just 5 µF.

Two Capacitors in Series
Ct=C1C2C1+C2C_{t} = \frac{C_{1} C_{2}}{C_{1} + C_{2}}
Where
  • CtC_{t}= Total capacitance
  • C1C_{1}= Capacitance 1
  • C2C_{2}= Capacitance 2
Missing one of these? Work it out first, then come back