Dose Achieved from Chemical Added

C=mV ρwC = \frac{m}{V \, \rho_w}

Worked example: 10 lb into 5000 gal → 239.81 ppm — press Try an example to run it live, then adjust anything.

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Dose Achieved from Chemical Added explained

mVC

Run the feed equation backwards and you get the after-the-fact question every technician is asked: I dumped a pail in — where does that put me? Ten pounds of product into a 5000 gallon system is 10 lb spread through 5000 × 8.34 = 41,700 lb of water, which is 10/41,700 = 240 ppm. In metric the same idea is even simpler, since a cubic metre of water weighs about 1000 kg: one kilogram in ten cubic metres is 100 ppm.

The number that wrecks this calculation is never the arithmetic — it is the system volume. Nameplate volumes on closed loops are optimistic, and towers with deep sumps, remote basins or long buried runs routinely hold 30–50% more than the drawings say. If accuracy matters, measure it: add a known mass of an inert tracer such as lithium or a fluorescent dye, let it mix for a full turnover, test the residual, and solve this same equation for V. That trick is the basis of every tracer-controlled feed program on the market.

Dose Achieved from Chemical Added formula

C=mV ρwC = \frac{m}{V \, \rho_w}
Where
  • CC= Concentration achieved (%)
  • mm= Mass of chemical added (kg)
  • VV= System volume (L)

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