Angle Between Clock Hands

Also known as angle between the hands of a clock · clock angle problem · clock hands angle formula · angle between hour and minute hand

θ=min(30H5.5M,  36030H5.5M)\theta = \min\left(\left|30H - 5.5M\right|,\; 360 - \left|30H - 5.5M\right|\right)

Worked example: 3:00 → hands exactly 90 degrees apartpress Try an example to run it live, then adjust anything.

Enter your known values, leave one input blank, and solves for the missing one. Tap a variable’s symbol to see what it means, with a typical value. Try different units for next level excitement!

Learning zone

The whole puzzle is that both hands move. The minute hand sweeps 6° per minute; the hour hand creeps 0.5° per minute — so the minute hand GAINS 5.5° on the hour hand every minute, and that 5.5 is the only number in the formula doing real work. At H o'clock the hour hand starts 30H degrees around; M minutes later the gap is |30H − 5.5M|, folded to the small side because an angle between hands is always reported as the one under 180°.

Where people go wrong: freezing the hour hand. At 3:30 the answer 'feels like' 90° minus something on the 6 — but the hour hand has spent half an hour drifting toward the 4, and the true gap is 75°. Any answer computed with a parked hour hand is off by up to 30°, which on this puzzle is the difference between right and embarrassingly wrong.

Angle Between Clock Hands
θ=min(30H5.5M,  36030H5.5M)\theta = \min\left(\left|30H - 5.5M\right|,\; 360 - \left|30H - 5.5M\right|\right)
Where
  • θ\theta= Angle between the hands (°)
  • HH= Hour on the face
  • MM= Minutes past the hour
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