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Cylinder Surface Area

S=2πr2+2πrhS = 2 \pi r^{2} + 2 \pi r h

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Constant used — built into this formula, no need to enter
π=3.141592653589793\pi = 3.141592653589793Pi · exact

Learning zone

Unroll a closed can and the surface splits into two circular end caps (2πr²) plus a rectangular label of width 2πr and height h wrapped around the side (2πrh). Example: a can with r = 4 cm and h = 11 cm needs 2π(16) + 2π(4)(11) ≈ 377 cm² of tin. Solving for r is a quadratic, but it has exactly one positive root, so the value returned is the unambiguous physical radius.

Cylinder Surface Area
S=2πr2+2πrhS = 2 \pi r^{2} + 2 \pi r h
Where
  • SS= Total surface area
  • rr= Radius
  • hh= Height
Missing one of these? Work it out first, then come back