Escape Velocity
Worked example: Earth surface escape → v = 11 186 m/s. Press Try an example to run it live, then adjust anything.
Enter your known values, leave one input blank, and solves for the missing one. Tap a variable’s symbol to see what it means, with a typical value. Change any unit and the answer follows.
Where Escape Velocity fits
- Gravitation and orbital mechanics8 formulas
See also
Gravitational Field Strength: Both use central mass and starting distance.Gravitational Potential Energy (Orbital): Both use central mass and starting distance.Orbital Period: Both use central mass and starting distance.Orbital Velocity: Both use central mass and starting distance.Leaving for good →
Grade 12Grade 12 Physics
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Escape Velocity explained
Escape velocity comes from an energy balance: launch with kinetic energy ½mv² at least equal to the gravitational well's depth GMm/r, and the projectile coasts to infinity with nothing to spare. The projectile's own mass cancels, and the direction of launch doesn't matter: only the speed. For Earth, v = √(2 × 6.674 × 10⁻¹¹ × 5.97 × 10²⁴ / 6.371 × 10⁶) ≈ 11 190 m/s, the familiar 11.2 km/s that every Moon-bound Apollo mission had to approach.
Note the √2: escape speed is exactly √2 times circular orbital speed at the same radius. The formula also sorts the solar system's atmospheres: the Moon's gentle 2.4 km/s could not hold onto gas molecules, while Jupiter's crushing 59.5 km/s keeps even hydrogen. Push the logic to its limit by asking where escape velocity reaches the speed of light, and you arrive at the Schwarzschild radius of a black hole.
Escape Velocity formula
- = Escape velocity (m/s)
- = Central mass (kg)
- = Starting distance (m)
Cite this page
formula.expert. (2026, October 16). Escape Velocity Formula & Calculator. https://formula.expert/solvers/escape-velocity