Force Between Parallel Wires

F=μ0I1I22πdF = \frac{\mu_0 I_1 I_2 \ell}{2\pi d}

Enter your known values, leave one input blank, and solves for the missing one. Try different units for next level excitement!

Learning zone

Each wire sits in the magnetic field of the other, so they push on each other: parallel currents attract, antiparallel repel. The effect is feeble at bench scale — two wires 1 cm apart carrying 10 A feel just 2 mN per meter — but from 1948 to 2019 it literally defined the ampere. It still matters at scale: adjacent turns in a transformer slam together during a short circuit, and busbars in switchgear must be braced against fault currents that can bend steel.

Force Between Parallel Wires
F=μ0I1I22πdF = \frac{\mu_0 I_1 I_2 \ell}{2\pi d}
Where
  • FF= Force
  • I1I_1= Current 1
  • I2I_2= Current 2
  • \ell= Wire length
  • dd= Separation