Loading Dose from Volume of Distribution

Also known as loading dose · Vd times Cp · bolus dose calculation · pharmacokinetics loading dose

DL=VdCpD_L = V_d \cdot C_p

Enter your known values, leave one input blank, and solves for the missing one. Try different units for next level excitement!

Learning zone

The volume of distribution is not a volume you could pour out. It is the volume the drug would have to occupy if all of it sat in plasma at the concentration you measured there. Drugs that bind heavily to tissue leave little in the plasma, so the apparent volume comes out enormous: digoxin is around 500 L in a person who contains perhaps 42 L of water, and amiodarone is larger still. That is not a paradox, it is a statement about where the drug went.

Given that, the loading dose is one multiplication. To reach 10 mg/L in a drug with a 35 L volume of distribution takes 35 imes10=35035 \ imes 10 = 350 mg, and the answer is independent of clearance because a loading dose is about filling the space, not about keeping it filled. That is the useful split: the loading dose sets how fast you arrive at the target, the maintenance rate sets where you stay.

Two things go wrong in practice. Volumes of distribution are population averages that shift with fluid status, obesity, age and renal function, and a value from a textbook can be off by half in a specific patient. And the arithmetic assumes instant, complete mixing, which is false for the first minutes to hours after a bolus. A drug given fast enough to hit a high plasma peak before it distributes can be toxic at a dose that is perfectly safe once mixed, which is why loading doses are often split or infused slowly. Choosing and giving one is a clinical decision; this page only does the multiplication.

Loading Dose from Volume of Distribution
DL=VdCpD_L = V_d \cdot C_p
Where
  • DLD_L= Loading dose (mg)
  • VdV_d= Volume of distribution (L)
  • CpC_p= Target plasma concentration (mg/L)