Logarithm of a Product

log⁡b(xy)=log⁡bx+log⁡by\log_b(xy) = \log_b x + \log_b y

Worked example: log₁₀(20 × 50) → 3 — press Try an example to run it live, then adjust anything.

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Logarithm of a Product explained

yxxylogb xlogb yL

This is the identity logarithms were invented for. Because bm×bn=bm+nb^m \times b^n = b^{m+n}, taking logs of a product adds the logs of its factors: log₁₀(20 × 50) = log₁₀20 + log₁₀50 = 1.301 + 1.699 = 3, which is log₁₀1000. Multiplying two awkward numbers becomes looking up two logs, adding, and looking the answer back up.

Sixteenth-century astronomers were doing exactly that trick already, using a trigonometric identity called prosthaphaeresis to convert products into sums of cosines; Napier's tables in 1614 made it general, and Henry Briggs's base-10 recasting a few years later put the method in every navigator's chart room for the next three and a half centuries. The traps are the ones every algebra course flags: log(x + y) is not log x + log y, and log x × log y is not log(xy) either — the rule converts multiplication inside the log into addition outside it, never the reverse. Both factors must also be positive; log(−4) + log(−9) is undefined even though log 36 is perfectly fine.

Logarithm of a Product formula

log⁡b(xy)=log⁡bx+log⁡by\log_b(xy) = \log_b x + \log_b y
Where
  • LL= Log of the product
  • xx= First factor
  • yy= Second factor
  • bb= Base