Logarithmic Decrement

Also known as log decrement · logarithmic decrement · damping from decay · ring-down test · amplitude decay ratio · measure damping from a bump test

δ=1nln ⁣(x1x2)\delta = \frac{1}{n} \ln\!\left(\frac{x_1}{x_2}\right)

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Damping is the one parameter in vibration analysis that cannot be calculated from a drawing. Mass comes off the weights, stiffness off the geometry and the modulus, but damping depends on joints, welds, coatings, bolt tension and how the machine happens to be sitting — so it has to be measured. The logarithmic decrement is how: hit the structure, let it ring down, and read the decay off the trace. δ=1nln(x1/x2)\delta = \frac{1}{n}\ln(x_1/x_2).

The reason a logarithm appears is that a damped free oscillation decays exponentially, x(t)=Xeζωntcos(ωdt+ϕ)x(t) = X e^{-\zeta\omega_n t}\cos(\omega_d t + \phi). Successive peaks are one damped period apart, so their ratio is the same constant every cycle — the third peak is the same fraction of the second as the second is of the first. Taking the natural log of that constant ratio turns a multiplicative decay into a number that simply adds up cycle by cycle, which is why dividing by nn works and why averaging over many cycles is legitimate.

The result you actually want is the damping ratio, and it comes from ζ=δ/4π2+δ2\zeta = \delta/\sqrt{4\pi^2 + \delta^2}. For light damping this simplifies to ζδ/2π\zeta \approx \delta/2\pi, which is within 1% up to about ζ=0.2\zeta = 0.2 and is the form usually quoted. A decrement of 0.1 means a damping ratio of about 0.016 — and it also means each swing is about 90% of the one before, which is a decay slow enough that a bystander would call the machine "ringy".

Three things spoil the measurement. Use several cycles rather than two adjacent peaks: any single peak carries noise, and n=5n = 5 or 10 averages it out. Compare peaks on the SAME side of the zero line, because a trace riding on a DC offset gives different answers for its two halves. And make sure it really is a free decay — the machine off, nearby equipment off, no forcing of any kind — since anything still driving the structure contaminates the record. One more reading is worth knowing: if the amplitude GROWS during a free decay, that is not a sign error. It is self-excitation — oil whirl, stick-slip, aerodynamic flutter — and it is a far more serious problem than the damping measurement it interrupted.

Logarithmic Decrement
δ=1nln ⁣(x1x2)\delta = \frac{1}{n} \ln\!\left(\frac{x_1}{x_2}\right)
x1x2nxt
Where
  • δ\delta= Logarithmic decrement
  • x1x_1= First peak amplitude (mm)
  • x2x_2= Later peak amplitude (mm)
  • nn= Cycles between the peaks
Missing one of these? Work it out first, then come back