Earthwork Volume by the Prismoidal Formula

V=L (A1+4Am+A2)6V = \frac{L\,(A_1 + 4A_m + A_2)}{6}

Worked example: 600 m³ over 30 m with 15 and 25 m² ends → 20 m² midsection — press Try an example to run it live, then adjust anything.

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Earthwork Volume by the Prismoidal Formula explained

A1AmA2VL

The prismoidal formula is exact for any solid whose cross-sectional area varies as a quadratic along its length — which covers the wedges, prisms, pyramids and transition sections that make up almost all real earthwork. It is Simpson's rule with a surveyor's vocabulary, and the 1-4-1 weighting is what makes it exact where the trapezoidal average end area is merely close. Note the subtlety that catches everyone: Am is the area of the section physically measured at the midpoint, not the average of A₁ and A₂. Substitute the average and the whole thing algebraically collapses back into the end area method.

A worked example: end areas of 120 ft² and 180 ft² one station apart, with the section actually taken at 0+50 measuring 140 ft². V = 100 × (120 + 4 × 140 + 180)/6 = 14,333 ft³ = 530.9 yd³, some 4.4 % less than the 555.6 yd³ the end area method returns. That difference — the prismoidal correction — is why large-quantity contracts and borrow pit pay quantities specify this method: on a million-yard job, four percent is the profit.

Earthwork Volume by the Prismoidal Formula

V=L (A1+4Am+A2)6V = \frac{L\,(A_1 + 4A_m + A_2)}{6}
Where
  • VV= Volume between sections (yd³)
  • A1A_1= Area of the first section (m²)
  • AmA_m= Area of the middle section (m²)
  • A2A_2= Area of the second section (m²)
  • LL= Distance between end sections (m)

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