Vertical Velocity Component

vy=vsinθv_y = v \sin\theta

Enter your known values, leave one input blank, and solves for the missing one. Try different units for next level excitement!

Learning zone

The vertical slice of the launch velocity, v sin θ, is the only part gravity ever touches — it decides how high the projectile climbs and how long it hangs in the air. A ball thrown at 20 m/s and 30° leaves with v_y = 20 × sin 30° = 10 m/s, rises for about a second, then comes back down through the launch height at 10 m/s downward, the flight being perfectly symmetric in a vacuum.

Long-jumpers live inside this trade-off: too shallow an angle and v_y is too small to stay airborne, too steep and the horizontal component collapses. Real jumpers take off near 20°, not the textbook 45°, because a human leg cannot generate the same launch speed in a steep, heavily loaded push-off — a reminder that the mathematically optimal angle is optimal only when v is genuinely independent of θ.

Vertical Velocity Component
vy=vsinθv_y = v \sin\theta
Where
  • vyv_y= Vertical velocity
  • vv= Launch speed
  • θ\theta= Launch angle