Vertical Velocity Component

vy=vsin⁡θv_y = v \sin\theta

Worked example: 20 m/s at 30° → 10 m/s — press Try an example to run it live, then adjust anything.

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Vertical Velocity Component explained

θvvy

The vertical slice of the launch velocity, v sin θ, is the only part gravity ever touches — it decides how high the projectile climbs and how long it hangs in the air. A ball thrown at 20 m/s and 30° leaves with vyv_y = 20 × sin 30° = 10 m/s, rises for about a second, then comes back down through the launch height at 10 m/s downward, the flight being perfectly symmetric in a vacuum.

Long-jumpers live inside this trade-off: too shallow an angle and vyv_y is too small to stay airborne, too steep and the horizontal component collapses. Real jumpers take off near 20°, not the textbook 45°, because a human leg cannot generate the same launch speed in a steep, heavily loaded push-off — a reminder that the mathematically optimal angle is optimal only when v is genuinely independent of θ.

Vertical Velocity Component formula

vy=vsin⁡θv_y = v \sin\theta
Where
  • vyv_y= Vertical velocity (m/s)
  • vv= Launch speed (m/s)
  • θ\theta= Launch angle (°)