Pump Efficiency from Hydraulic and Shaft Power

η=PhydPshaft\eta = \frac{P_{hyd}}{P_{shaft}}
sig figs

Worked example: 15 kW delivered from 20 kW at the shaft → eta = 0.75. Press Try an example to run it live, then adjust anything.

Enter your known values, leave one input blank, and solves for the missing one. Tap a variable’s symbol to see what it means, with a typical value. Change any unit and the answer follows.

Where Pump Efficiency from Hydraulic and Shaft Power fits

Missing an input?
Your answer feeds
In this toolkit

See also

Pump Brake Horsepower: Both use pump efficiency and shaft power.Pump Water Horsepower: Both use hydraulic power.Hydraulic Power (P = ρgQh): Both use hydraulic power.Fan Affinity Law: Power vs Speed: Both use shaft power.Fan Brake Horsepower: Both use shaft power.Pump Affinity Law: Power vs Speed: Both use shaft power.
Here the solver did the work. Could you?

Shaft power and efficiency →

UniversityFluid Mechanics, HVAC & Refrigeration

Test your skills in the Exam Room: new numbers every attempt. Free lessons for students, no sign-up, just pure learning.

See your Report Card
Learning zone

Pump Efficiency from Hydraulic and Shaft Power explained

PshaftPhydη

Everything a pump fails to put into the water it puts into heat, noise and vibration. A unit delivering 15 kW of hydraulic power while absorbing 20 kW at the shaft is 75% efficient, and the missing 5 kW is warming the casing and the liquid. Large water-supply pumps reach 85–90%; small close-coupled circulators struggle to pass 40%; and any positive-displacement chemical metering pump is efficient in a different sense entirely.

The trap is comparing efficiencies measured at different boundaries. Pump efficiency is hydraulic over shaft; wire-to-water efficiency multiplies that by the motor and drive efficiencies and is the number that matters on the electricity bill. A 75% pump on a 92% motor behind a 97% VFD is 67% wire-to-water, so if you are calculating operating cost from a "75% efficient" pump, you will underestimate the annual energy by about 12%.

Pump Efficiency from Hydraulic and Shaft Power formula

η=PhydPshaft\eta = \frac{P_{hyd}}{P_{shaft}}
Where
  • η\eta= Pump efficiency
  • PhydP_{hyd}= Hydraulic power (W)
  • PshaftP_{shaft}= Shaft power (W)
Revised 30 October 2026
Cite this page

formula.expert. (2026, October 30). Pump Efficiency from Hydraulic and Shaft Power Calculator. https://formula.expert/solvers/pump-efficiency-power