Seepage Velocity from Discharge Velocity
Worked example: v 0.02 cm/s in n = 0.40 → vs = 0.05 cm/s. Press Try an example to run it live, then adjust anything.
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Where Seepage Velocity from Discharge Velocity fits
- Darcy's law and seepage4 formulas
See also
Void Ratio and Porosity (e = n/(1 − n)): Both use porosity.Seepage Velocity from Discharge Velocity explained
Darcy's velocity v = ki is discharge divided by the gross area, which pretends the water flows through the grains as well as around them. It does not: only the pore space conducts, so the water that actually gets through has to move faster by exactly the reciprocal of the porosity. A discharge velocity of 0.02 cm/s in a soil with n = 0.40 means real particles of water are moving at 0.05 cm/s: two and a half times faster.
The trap is contaminant travel time. Use v instead of to work out when a plume reaches the property line and you will be late by a factor of two or three, which is the difference between a monitoring programme and a lawsuit. The second trap is tortuosity: even is an average along a straight line, while a water molecule actually threads a winding path perhaps 1.2–1.5 times longer, so true particle speeds are higher again. For a first-pass arrival time is the right number; for a defensible one, add a dispersion model.
Seepage Velocity from Discharge Velocity formula
- = Seepage velocity (cm/s)
- = Discharge velocity (cm/s)
- = Porosity
Cite this page
formula.expert. (2026, October 16). Seepage Velocity from Discharge Velocity Calculator. https://formula.expert/solvers/seepage-velocity