Magnetic Field of a Solenoid

B=μ0NILB = \frac{\mu_0 N I}{L}

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Wind wire into a tight helix and the fields of all the turns add up inside while cancelling outside, leaving a remarkably uniform interior field that depends only on turns per length and current — not on the coil's diameter. A 20 cm coil of 1000 turns at 5 A produces μ₀ × 1000 × 5 / 0.2 ≈ 31 mT, several hundred times Earth's field. Wrap the same coil around an iron core and the field multiplies a thousandfold — the recipe for electromagnets, relays, and MRI bores (which swap iron for superconducting current).

Magnetic Field of a Solenoid
B=μ0NILB = \frac{\mu_0 N I}{L}
Where
  • BB= Magnetic field
  • NN= Number of turns
  • II= Current
  • LL= Solenoid length
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