Solubility Product of an AB₂ Salt
Enter your known values, leave one input blank, and solves for the missing one. Try different units for next level excitement!
Learning zone
When a salt dissolves into three ions instead of two the arithmetic changes shape. CaF₂(s) ⇌ Ca²⁺ + 2F⁻ releases one calcium and two fluorides per formula unit, so if s moles dissolve per litre then [Ca²⁺] = s but [F⁻] = 2s, and Ksp = s(2s)² = 4s³. Calcium fluoride's molar solubility of 2.15 × 10⁻⁴ M therefore gives Ksp = 4(2.15 × 10⁻⁴)³ = 4.0 × 10⁻¹¹, matching the handbook value.
Reversed, Mg(OH)₂ with Ksp = 5.6 × 10⁻¹² dissolves to s = ∛(5.6 × 10⁻¹² / 4) = 1.1 × 10⁻⁴ M — enough hydroxide to buffer a stomach at pH about 10 in the flask, which is the entire pharmacology of milk of magnesia. The universal trap is dropping the 4, or forgetting that the doubled ion gets both a coefficient and an exponent. Also note that Ksp alone does not rank solubility across different stoichiometries: AgCl (Ksp 1.7 × 10⁻¹⁰) is actually less soluble than Mg(OH)₂ despite the larger constant, because the exponents differ.
- = Solubility product
- = Molar solubility
- Solubility product — Solubility Product of a 1:1 Salt, Reaction Quotient Q (aA + bB ⇌ cC)
- Molar solubility — Solubility Product of a 1:1 Salt, Molarity (C = n/V)