Thin-Film Destructive Interference (Dark Reflection)

2nt=mλ2 n t = m \lambda

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This is the same optical path difference as the bright case, 2nt in the film's own wavelength, but read the other way. Because only the top surface inverts its reflection, a whole number of wavelengths in the path leaves the two reflected waves exactly out of step, and that colour disappears from the reflection. Everything it disappears from, it appears in — the missing light is transmitted, not destroyed, which is why a soap film looks complementary in reflection and in transmission.

Anti-reflection coatings are this equation used deliberately, with one wrinkle: a magnesium fluoride layer (n = 1.38) on glass (n = 1.52) inverts at both surfaces, so the half-wave cancels out and the dark condition becomes 2nt = (m + ½)λ instead — the famous quarter-wave coating t = λ/4n. Count your inversions before you pick a condition; that single bookkeeping step is where most of the marks go.

Worked case: a soap film with n = 1.33 seen in 600 nm orange light goes dark in first order at t = (1)(600 nm)/(2 × 1.33) = 226 nm. Newton pressed a lens onto a flat plate and saw the equivalent air wedge produce ring after ring — and at the exact point of contact, where t = 0, a black spot. That black centre is m = 0 in this equation and was the one feature Newton's particle theory could never explain.

Thin-Film Destructive Interference (Dark Reflection)
2nt=mλ2 n t = m \lambda
Where
  • tt= Film thickness
  • nn= Index of refraction of the film
  • mm= Interference order
  • λ\lambda= Wavelength in vacuum