Torque with a Lever Arm (τ = rF sin θ)

τ=rFsinθ\tau = r F \sin\theta

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Learning zone

Only the component of force perpendicular to the lever actually turns it — hence the sin θ. Push straight along a wrench handle (θ = 0) and nothing rotates; push at right angles (θ = 90°) and every newton counts. That is why a longer wrench loosens a stuck bolt with the same effort: doubling r doubles τ. A 200 N push at the end of a 30 cm wrench, applied perpendicular, delivers 60 N·m.

Torque with a Lever Arm (τ = rF sin θ)
τ=rFsinθ\tau = r F \sin\theta
Where
  • τ\tau= Torque
  • rr= Lever arm length
  • FF= Force
  • θ\theta= Angle
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