Volumetric Organic Loading Rate
Enter your known values, leave one input blank, and solves for the missing one. Try different units for next level excitement!
Learning zone
Volumetric loading answers the question a designer actually asks: how big does the tank have to be? Take the pounds — or kilograms — of BOD arriving each day and divide by the reactor volume. A flow of 4320 m³/d at 200 mg/L delivers 864 kg BOD/d, and in a 1200 m³ aeration basin that is 0.72 kg BOD/(m³·d). Conventional activated sludge sits at 0.3–1.0, extended aeration well below 0.3, high-rate systems above 1.5, a rock trickling filter around 0.2–0.5, and a mesophilic anaerobic digester on volatile solids at 1.6–3.2.
The value of the number is that it collapses two variables — flow and strength — into one, so it exposes what a hydraulic detention time hides. Two plants with identical two-hour detention times are not comparable if one treats 150 mg/L domestic sewage and the other 900 mg/L cannery waste. Push the loading past design and the symptoms are textbook: dissolved oxygen collapses, filamentous organisms take over because they out-compete floc-formers at low DO, sludge stops settling, and solids leave over the clarifier weir. The classic mistake is loading a digester by volume of sludge pumped rather than by pounds of volatile solids — a thin, watery feed can double the pumping and still starve the bugs, while a good thickener can overload the same digester at half the flow.
- = Volumetric loading (kg BOD/m³·d)
- = Flow rate
- = Influent BOD concentration
- = Reactor volume
- Volumetric loading (kg BOD/m³·d) — Clarifier Solids Loading Rate, CT Value for Disinfection Credit
- Flow rate — Hydraulic Detention Time, Surface Overflow Rate
- Influent BOD concentration — Food-to-Microorganism (F/M) Ratio, BOD Removal Efficiency
- Reactor volume — Sewer Credit for Evaporated Water, Net Water and Sewer Cost of a Cooling Tower