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ft⋅lbf/lb\text{ft}{\cdot}\text{lbf/lb}

foot pound-force per pound

Specific latent heat

The foot pound-force per pound is 2.989066923 J/kg, the specific energy that falls out of US pump work: a pump head of one foot delivers one ft·lbf per pound of fluid. It is why "head in feet" and "specific energy" are the same statement in imperial practice.

Watch out: Pound-force per pound-mass looks dimensionless and is not. The conversion carries standard gravity inside it, so the identity of head with specific energy only holds at g = 9.80665 m/s².

1 ft⋅lbf/lb\text{ft}{\cdot}\text{lbf/lb} 2.9890669 J/kg\text{J/kg}

One foot pound-force per pound in every specific latent heat unit

2.98907joule per kilogram (J/kg)
1foot pound-force per pound (ft·lbf/lb)this unit
0.00298907kilojoule per kilogram (kJ/kg)
0.00298907joule per gram (J/g)
0.00128507BTU per pound (BTU/lb)
0.000830296watt-hour per kilogram (W·h/kg)
0.000714404calorie per gram (cal/g)
0.000714404kilocalorie per kilogram (kcal/kg)
0.00000298907megajoule per kilogram (MJ/kg)
8.30296e-07kilowatt-hour per kilogram (kW·h/kg)
Solvers that use specific latent heat

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