Angular Acceleration

α=ω−ω0t\alpha = \frac{\omega - \omega_0}{t}

Worked example: 0 to 20 rad/s in 4 s → alpha = 5 rad/s^2 — press Try an example to run it live, then adjust anything.

Enter your known values, leave one input blank, and solves for the missing one. Tap a variable’s symbol to see what it means, with a typical value. Try different units for next level excitement!

Here the solver did the work — could you?

Angular kinematics →

UniversityEngineering Mechanics

Test your skills in the Exam Room: new numbers every attempt — free lessons for students, no sign-up, just pure learning.

See your Report Card
Compete with your friends
share your results
Learning zone

Angular Acceleration explained

ω0ωαt

Angular acceleration is how quickly a rotation rate is changing, α=(ω−ω0)/t\alpha = (\omega - \omega_0)/t. It is the exact rotational mirror of a=(v−v0)/ta = (v - v_0)/t, and that mirroring is not a coincidence or a mnemonic — the entire structure of linear kinematics carries across intact, with θ\theta in place of xx, ω\omega in place of vv, and α\alpha in place of aa. Every uniform-acceleration technique you already know works unchanged in the rotational world.

A hard-disk platter spinning up from rest to 7200 rpm in 4 s: convert first, ω=7200×0.10472≈754\omega = 7200 \times 0.10472 \approx 754 rad/s, so α=(754−0)/4≈188\alpha = (754 - 0)/4 \approx 188 rad/s². A large industrial fan coasting down from 1200 rpm (126 rad/s) to rest over 90 s has α=−1.4\alpha = -1.4 rad/s², and the negative sign is the whole of what distinguishes a spin-down from a spin-up.

What makes α\alpha worth computing is that it is the bridge to torque. Once you know the angular acceleration a duty cycle demands, τ=Iα\tau = I\alpha tells you the torque the drive must supply, and that is how motors get sized for anything that has to start and stop repeatedly — a centrifuge, a machine-tool spindle, a conveyor, a robot joint. The starting torque is very often larger than the running torque, and this equation is where that requirement first appears.

The unit mistake here has an extra layer to it. As always, ω\omega must be in rad/s before it goes anywhere near the formula, but the output also has to be read correctly: α\alpha comes out in rad/s², and a figure quoted as "rpm per second" is not the same quantity — it needs the same 0.10472 factor applied. A drive rated to accelerate at "500 rpm/s" is delivering 52.4 rad/s². The second issue is signs. Pick a positive direction of rotation and keep it: braking a shaft turning positively gives a negative α\alpha, and the calculator's own answer will tell you if you have them mixed, because a spin-down entered with both velocities positive and a positive α\alpha is describing something that cannot happen. Finally, this is the average angular acceleration over the interval. A real motor's torque varies enormously with speed, so the instantaneous α\alpha during a start is nothing like constant; the average is the right number for a duty-cycle estimate and the wrong one for a stress calculation at the moment of highest load.

Angular Acceleration formula

α=ω−ω0t\alpha = \frac{\omega - \omega_0}{t}
Where
  • α\alpha= Angular acceleration (rad/s²)
  • ω\omega= Final angular velocity (rad/s)
  • ω0\omega_0= Initial angular velocity (rad/s)
  • tt= Time (s)