Final Velocity (Uniform Acceleration)

Also known as first kinematic equation · v = v₀ + at · SUVAT v = u + at

v=v0+atv = v_0 + a t

Worked example: Car merging: 15 m/s + 2 m/s² for 5 s → 25 m/s — press Try an example to run it live, then adjust anything.

Enter your known values, leave one input blank, and solves for the missing one. Tap a variable’s symbol to see what it means, with a typical value. Try different units for next level excitement!

Here the solver did the work — could you?

The Loading Dock →

Grade 11Grade 11 Physics

Velocity as the derivative →

Grade 12Grade 12 Math

Kinematics revisited →

UniversityEngineering Mechanics

Test your skills in the Exam Room: new numbers every attempt — free lessons for students, no sign-up, just pure learning. Find 4 more lessons on this formula.

See your Report Card
Compete with your friends
share your results
Learning zone

Final Velocity (Uniform Acceleration) explained

v0vat

Under constant acceleration, velocity changes at a steady rate, so the final speed is simply the starting speed plus the acceleration multiplied by the elapsed time. Picture a car merging onto a highway: entering the ramp at 15 m/s and holding a steady 2 m/s² for 5 seconds, it reaches v = 15 + (2)(5) = 25 m/s — right at highway pace. Deceleration works the same way with a negative a, which is how stopping times are estimated from braking data.

This is the first of the SUVAT equations, the toolkit of uniformly accelerated motion that traces back to Galileo's inclined-plane experiments in the early 1600s, where he showed that falling bodies gain equal speed in equal times. Because the relationship is linear in every variable, each of the four rearrangements has exactly one answer — no square roots, no ambiguity — making it the friendliest member of the kinematics family.

Final Velocity (Uniform Acceleration) formula

v=v0+atv = v_0 + a t
Where
  • vv= Final velocity (m/s)
  • v0v_0= Initial velocity (m/s)
  • aa= Acceleration (m/s²)
  • tt= Time (s)