Arithmetic Series Sum

Sn=n2(2a1+(n1)d)S_n = \frac{n}{2} \left( 2 a_1 + (n - 1) d \right)

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The sum of an arithmetic series is the average of the first and last terms times the number of terms — the trick young Gauss reportedly used to add 1 through 100 in seconds: S = (100/2)(1 + 100) = 5050. In the general form, the last term is unpacked as a₁ + (n − 1)d.

It answers stacking questions directly: a log pile with 15 logs on the bottom row and one fewer per row for 10 rows holds S = (10/2)(2 × 15 + 9 × (−1)) = 105 logs.

Arithmetic Series Sum
Sn=n2(2a1+(n1)d)S_n = \frac{n}{2} \left( 2 a_1 + (n - 1) d \right)
Where
  • SnS_n= Sum of the first n terms
  • nn= Number of terms
  • a1a_1= First term
  • dd= Common difference
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