Arps Hyperbolic Decline Curve (Well Rate over Time)

Also known as Arps decline curve · hyperbolic decline · decline curve analysis · decline exponent b · Arps equation · production decline forecast · well decline curve · oil well decline rate · gas well decline rate · qi Di b · nominal decline rate · hyperbolic decline of a well

q=qi(1+b Di t)1/bq = \frac{q_i}{\left(1 + b\,D_i\,t\right)^{1/b}}
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Worked example: 1 000 bbl/d, 0.5 per year, b 0.5, 2 years → 444.44 bbl/d. Press Try an example to run it live, then adjust anything.

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Where Arps Hyperbolic Decline Curve (Well Rate over Time) fits

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See also

Arps Exponential Decline Curve (Well Rate over Time): The b = 0 limit: the decline rate never slows, so the rate falls by the same fraction every year.Arps Harmonic Decline Curve (Well Rate over Time): The b = 1 limit: the decline rate slows as fast as the Arps family allows.Exponential Decay: The same b = 0 curve written for any quantity that loses a fixed fraction of itself each period.Capacity Factor: A field's output against its nameplate: the check to run beside a decline forecast.
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Arps Hyperbolic Decline Curve (Well Rate over Time) explained

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Every oil or gas well gives less as it ages, and this formula says how quickly, in the form J. J. Arps published in 1945. The well starts on decline at a rate qiq_i and, at that moment, loses a fraction DiD_i of its rate per unit time: the initial nominal decline rate. The exponent bb says how fast that decline rate itself slows as the well ages. At b=0b = 0 it never slows and the curve is exponential. At b=1b = 1 it slows as fast as it can and the curve is harmonic. Between the two, the classical range of bb from 0 to 1, the curve is the hyperbola this page solves.

The exponential and harmonic curves have pages of their own, because at b=0b = 0 the exponent 1/b1/b cannot be formed, so the exponential is a limit of this formula, and at b=1b = 1 the formula gives exactly the simpler harmonic curve. Time and the decline rate must be in the same unit, so 0.12 per month goes with months and 1.44 per year with years. Take a well that starts at 1 000 barrels a day with Di=0.5D_i = 0.5 per year and b=0.5b = 0.5. After two years the bracket 1+b Di t1 + b\,D_i\,t is 1+0.5×0.5×21 + 0.5 \times 0.5 \times 2, and raising it to the power 1/b=21/b = 2 gives 2.25. The rate is 1 000 divided by 2.25, which is 444.444 barrels a day. Run backwards, the same 444.444 after two years means an initial rate of 1 000, and at the same DiD_i and bb the time to fall to 100 barrels a day is 8.649111 years.

The real numbers come from Fetkovich's 1980 type-curve match of Arps' own hyperbolic example: an initial rate of 30 303 barrels a month, DiD_i of 0.12 per month and b=0.5b = 0.5. At 100 months the curve gives 30 303 divided by 49, which is 618.43 barrels a month. The same paper shows how much the choice of curve matters: at a limit of 20 barrels a month, the exponential curve gives a life of 285 months, against 1 480 months for the harmonic.

A fitted bb above 1 turns up for wells whose early flow is still transient, such as wells in very tight rock. The page allows it: with b=1.5b = 1.5 and the same 1 000 barrels a day, 0.5 per year and two years, the rate is 542.88 barrels a day. The caution is that such a curve gives an unbounded total volume, so it must be ended by an economic limit or by a switch to exponential decline.

Arps Hyperbolic Decline Curve (Well Rate over Time) formula

q=qi(1+b Di t)1/bq = \frac{q_i}{\left(1 + b\,D_i\,t\right)^{1/b}}
Where
  • qq= Rate at time t (m³/d)
  • qiq_i= Initial rate (m³/d)
  • DiD_i= Initial nominal decline rate (1/yr)
  • bb= Decline exponent
  • tt= Time on decline (yr)
Where this comes from
  • Arps, J. J. (1945). Analysis of decline curves. Transactions of the AIME, 160(1), 228-247 (the exponential, hyperbolic and harmonic decline curves and the loss-ratio method; the DOI and abstract were checked in Crossref, the paper itself is behind the SPE paywall and was not opened here). Read it
  • Fetkovich, M. J. (1980). Decline curve analysis using type curves. Journal of Petroleum Technology, 32(6), 1065-1077 (equations 1 to 3 print Arps' rate-time equations: q/q_i = 1/(1 + b D_i t)^(1/b), exponential e^(-D_i t) for b = 0 and 1/(1 + D_i t) for b = 1; the worked type-curve match of Arps' hyperbolic example gives q_i = 30 303 barrels of oil per month, D_i = 0.12 per month and b = 0.5, and the exponential example gives a life of 285 months on the exponential curve against 1 480 months on the harmonic at a limit of 20 barrels a month; read on 23 Oct 2026 in a copy of the paper filed with the Texas A&M petroleum engineering lecture notes). Read it
Revised 30 October 2026
Cite this page

formula.expert. (2026, October 30). Arps Hyperbolic Decline Curve (Well Rate over Time) Calculator. https://formula.expert/solvers/arps-decline-hyperbolic