Bulk Modulus (K = ΔP·V₀/ΔV)
Worked example: 1 mL out of 1 L of water at 2.2 MPa → K = 2.2 GPa. Press Try an example to run it live, then adjust anything.
Enter your known values, leave one input blank, and solves for the missing one. Tap a variable’s symbol to see what it means, with a typical value. Change any unit and the answer follows.
Where Bulk Modulus (K = ΔP·V₀/ΔV) fits
- Stress, strain and the elastic constants9 formulas
Bulk Modulus (K = ΔP·V₀/ΔV) explained
Young's modulus describes stretching in one direction; the bulk modulus describes squeezing from every direction at once. The volumetric strain ΔV/V₀ is the three-dimensional cousin of ε, and K is the pressure needed per unit of it. Water's K ≈ 2.2 GPa means a 2.2 MPa (about 320 psi) pressure rise on one litre squeezes out just one millilitre: the origin of the schoolroom line that "liquids are incompressible". They are not, quite: seawater's compressibility is why sea level sits roughly 40 m lower than it would if the ocean were truly rigid.
Hydraulics is where this bites in the trades. Oil at K ≈ 1.5 GPa in a long, large-bore cylinder line stores real energy and makes a nominally stiff actuator feel spongy; entrained air, which is thousands of times more compressible, destroys the stiffness completely and is the first thing to suspect when a hydraulic system goes soft. The trap in the arithmetic is unit mismatch between V₀ and ΔV: enter 200 L and 0.63 L, or 0.2 m³ and 0.00063 m³, but never one of each with the same number.
Bulk Modulus (K = ΔP·V₀/ΔV) formula
- = Bulk modulus (kPa)
- = Pressure increase (kPa)
- = Original volume (L)
- = Volume reduction (L)
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formula.expert. (2026, October 16). Bulk Modulus (K = ΔP·V₀/ΔV) Formula & Calculator. https://formula.expert/solvers/bulk-modulus