Cooling Tower Heat Rejection
Enter your known values, leave one input blank, and solves for the missing one. Try different units for next level excitement!
Learning zone
This is the water-side sensible-heat equation wearing trade clothing. Q = ṁ·c·ΔT with mass flow in pounds per hour and c = 1 BTU/(lb·°F) becomes Q = 500 × gpm × ΔT°F, because a gallon of water weighs 8.34 lb and there are 60 minutes in an hour: 8.34 × 60 = 500.4, rounded to 500 forever. A 1000 gpm tower on a 10 °F range is therefore rejecting 500 × 1000 × 10 = 5,000,000 BTU/h — about 1465 kW, or 417 tons of refrigeration.
Two habits keep this honest. First, the constant assumes plain water near ambient temperature; a 30% propylene glycol loop has a specific heat near 0.9 BTU/(lb·°F) and a different density, so the real constant is closer to 460 and using 500 overstates the duty by roughly 8%. Second, on a chiller the tower rejects the evaporator load plus the compressor work, which is why condenser water flow is sized at 3 gpm/ton against 2.4 gpm/ton on the chilled-water side. The solver applies the 500 constant per gallon per minute per Fahrenheit degree regardless of the units you type, converting first.
- = Heat rejection rate
- = Recirculation rate
- = Cooling range
- Heat rejection rate — Chiller Heat Rejection, Boiler Horsepower to Heat Output
- Recirculation rate — Cooling Tower Evaporation Rate, Cooling Tower Drift Loss
- Cooling range — Cooling Tower Evaporation Rate, Cooling Tower Range