Dilution Equation (C1V1 = C2V2)
Also known as C₁V₁ = C₂V₂ · M₁V₁ = M₂V₂ · stock solution dilution
Worked example: 50 mL of 6.0 M diluted to 300 mL → 1.0 mol/L — press Try an example to run it live, then adjust anything.
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Dilution →
Grade 11Grade 11 Chemistry
Dilution discipline →
Grade 12Grade 12 Chemistry
The dilution line →
UniversityProcess & Water Chemistry
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Dilution Equation (C1V1 = C2V2) explained
Adding solvent to a solution spreads the same solute through a larger volume — the moles do not change, only their crowding. Since moles equal concentration times volume, must equal before and after any dilution. To prepare 250 mL of 1.0 M hydrochloric acid from a 12.1 M concentrated stock, solve for : (1.0 × 250)/12.1 ≈ 20.7 mL of stock, made up to the 250 mL mark with water. (And always add acid to water, never the reverse.)
The law is not limited to molarity — any concentration measure proportional to moles per volume works, as long as both sides use the same one. Water-treatment operators lean on it daily when dosing inhibitor or biocide from concentrated drums into recirculating loops, and biologists use the identical arithmetic for serial dilutions, where each step divides concentration by a fixed factor.
Dilution Equation (C1V1 = C2V2)
- = Initial concentration (M)
- = Initial volume (L)
- = Final concentration (M)
- = Final volume (L)
Missing one of these? Work it out first, then come back
- Initial concentration — Zero-Order Integrated Rate Law, First-Order Integrated Rate Law
- Initial volume — Boyle's Law, Charles's Law
- Final concentration — Mixing Two Solutions (C₁V₁ + C₂V₂ = C_f V_f), Molarity (C = n/V)
- Final volume — Glycol Dilution, Boyle's Law