Dry Unit Weight from Gs and Void Ratio

γd=Gs γw1+e\gamma_d = \frac{G_s\,\gamma_w}{1 + e}

Worked example: Gs = 2.65, e = 0.65 → γd = 15.76 kN/m³ — press Try an example to run it live, then adjust anything.

Enter your known values, leave one input blank, and solves for the missing one. Tap a variable’s symbol to see what it means, with a typical value. Try different units for next level excitement!

Learning zone

Dry Unit Weight from Gs and Void Ratio explained

Gseγd

GsγwG_s \gamma_w is the unit weight the soil would have with no voids at all — solid quartz, about 26 kN/m³ or 165 pcf. Spreading that solid over (1 + e) volumes of soil gives the dry unit weight. With GsG_s = 2.65, γw\gamma_w = 9.81 kN/m³ and e = 0.65 the result is 25.997 ÷ 1.65 = 15.76 kN/m³. Rearranged for e it becomes the laboratory workhorse: measure γd\gamma_d on a 105 pcf fill, take GsG_s = 2.70, and e = (2.70 × 62.4) ÷ 105 − 1 = 0.605.

The trap is that this is the dry unit weight even when the soil is wet — the water is in the voids, and it is deliberately not counted. Pair it with γ = γd\gamma_d(1 + w) when you need the bulk value. The second trap is treating GsG_s as a universal 2.65. It is close for quartz sands, but a soil with heavy minerals, mine tailings, or shell fragments will not behave, and a peat at GsG_s = 1.6 will hand you a void ratio that is nonsense. Run the pycnometer if the answer matters.

Dry Unit Weight from Gs and Void Ratio formula

γd=Gs γw1+e\gamma_d = \frac{G_s\,\gamma_w}{1 + e}
Where
  • γd\gamma_d= Dry unit weight (kN/m³)
  • GsG_s= Specific gravity of solids
  • γw\gamma_w= Unit weight of water (kN/m³)
  • ee= Void ratio