Elastic Potential Energy

U=12kx2U = \tfrac{1}{2} k x^{2}

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Compressing or stretching a spring stores energy equal to the average force (½kx) times the distance — hence the ½kx². The square matters: double the stretch and you bank four times the energy. A 400 N/m spring compressed 0.05 m stores 0.5 J. Solving for x takes the principal positive root, the displacement magnitude.

Elastic Potential Energy
U=12kx2U = \tfrac{1}{2} k x^{2}
Where
  • UU= Elastic potential energy
  • kk= Spring constant
  • xx= Displacement from rest
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