Displacement (Uniform Acceleration)
Also known as second kinematic equation · d = v₀t + ½at² · SUVAT s = ut + ½at²
Worked example: Plane from rest, 2.5 m/s² for 30 s → 1125 m — press Try an example to run it live, then adjust anything.
Enter your known values, leave one input blank, and solves for the missing one. Tap a variable’s symbol to see what it means, with a typical value. Try different units for next level excitement!
The height of a throw →
Grade 11Grade 11 Math — Functions & Applications
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UniversityEngineering Mechanics
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Displacement (Uniform Acceleration) explained
When acceleration is constant, displacement has two parts: the distance you would cover at your initial velocity alone, plus the extra distance contributed by speeding up — and that extra grows with the square of time. A jet starting its takeoff roll from rest and holding 2 m/s² covers d = 0 + ½(2)(30²) = 900 m in 30 seconds, which is why runways are measured in kilometres.
The ½ appears because the acceleration term is built from the average of a speed that grows linearly from zero. Galileo uncovered the underlying pattern — distances in successive equal time intervals follow the odd numbers 1, 3, 5, 7 — by rolling bronze balls down inclined planes. Note that solving for t would mean solving a quadratic with potentially two positive roots, so this calculator rearranges only for d, v₀, and a, where the answer is always single-valued.
Displacement (Uniform Acceleration) formula
- = Displacement (m)
- = Initial velocity (m/s)
- = Acceleration (m/s²)
- = Time (s)
Missing one of these? Work it out first, then come back
- Displacement — Velocity-Displacement Relation (v² = v₀² + 2ad), Displacement from Average Velocity
- Initial velocity — Final Velocity (Uniform Acceleration), Velocity-Displacement Relation (v² = v₀² + 2ad)
- Acceleration — Newton's Second Law, Final Velocity (Uniform Acceleration)
- Time — Speed, Distance & Time, Final Velocity (Uniform Acceleration)