Maximum Power Transfer to a Matched Load

Also known as matched load · impedance matching · Jacobi's law · maximum power theorem · source matching

Pmax=VTh24RThP_{max} = \frac{V_{Th}^{2}}{4 R_{Th}}

Worked example: 20 V behind 5 Ω → 20 W into a matched 5 Ω — press Try an example to run it live, then adjust anything.

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Maximum Power Transfer to a Matched Load explained

VThRThPmaxRTh

Sweep a load resistance from zero to infinity across a source and the power it receives rises, peaks, and falls again. Too small and the voltage collapses; too large and the current does. The peak sits exactly where RL=RThR_L = R_{Th}, and there the load takes VTh2/4RThV_{Th}^2/4R_{Th}. Twenty volts behind 5 Ω, matched by a 5 Ω load: the loop carries 2 A, and the load absorbs 22×5=202^2 \times 5 = 20 W.

Notice what else happened in that example — the source dissipated 20 W too. Matched transfer is 50% efficient, always, by construction. That is the classic misreading of this theorem: it maximises power delivered, not power saved. No utility matches its generators to the grid; a power system deliberately runs with source impedance far below load impedance so efficiency approaches 100% and voltage stays stiff. Matching belongs where the signal matters and the watts do not.

So it lives in RF and audio and instrumentation: antennas into 50 Ω feedlines, transmission lines terminated to stop reflections, a solar panel held at its maximum-power point by a tracking converter. And the AC version wants the load impedance to be the complex conjugate of the source, so a source that looks inductive must be met with capacitance — reactance cancelled first, resistance matched second.

Maximum Power Transfer to a Matched Load formula

Pmax=VTh24RThP_{max} = \frac{V_{Th}^{2}}{4 R_{Th}}
Where
  • PmaxP_{max}= Maximum load power (W)
  • VThV_{Th}= Thevenin voltage (V)
  • RThR_{Th}= Thevenin resistance (Ω)