Mole Fraction

x1=n1n1+n2x_1 = \frac{n_1}{n_1 + n_2}
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Worked example: 1 mol solute + 9 mol solvent → x1 = 0.1. Press Try an example to run it live, then adjust anything.

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Mole Fraction explained

n1n2x1

The mole fraction asks the simplest possible concentration question: of every mole of particles in the mixture, what share belongs to component 1? Dissolve 1.00 mol of ethylene glycol in 9.00 mol of water and x₁ = 1.00/(1.00 + 9.00) = 0.100: no units, no temperature dependence, and all the mole fractions in a mixture always sum to exactly 1.

This makes x the natural currency of vapor-pressure laws: Raoult's law and Dalton's law are both written in mole fractions, and gas mixtures are routinely quoted this way. Dry air is x ≈ 0.78 nitrogen and 0.21 oxygen. Solving the definition backwards for n₁ or n₂ requires x strictly between 0 and 1, since a pure component (x = 1) carries no information about how much solvent could be present.

Mole Fraction formula

x1=n1n1+n2x_1 = \frac{n_1}{n_1 + n_2}
Where
  • x1x_1= Mole fraction of solute
  • n1n_1= Amount of solute (mol)
  • n2n_2= Amount of solvent (mol)
Revised 16 October 2026
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formula.expert. (2026, October 16). Mole Fraction Formula & Calculator. https://formula.expert/solvers/mole-fraction